std::for_each
Defined in header <algorithm>
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(1) | ||
template< class InputIt, class UnaryFunction > UnaryFunction for_each( InputIt first, InputIt last, UnaryFunction f ); |
(until C++20) | |
template< class InputIt, class UnaryFunction > constexpr UnaryFunction for_each( InputIt first, InputIt last, UnaryFunction f ); |
(since C++20) | |
template< class ExecutionPolicy, class ForwardIt, class UnaryFunction2 > void for_each( ExecutionPolicy&& policy, ForwardIt first, ForwardIt last, UnaryFunction2 f ); |
(2) | (since C++17) |
f
to the result of dereferencing every iterator in the range [first, last)
, in order. f
to the result of dereferencing every iterator in the range [first, last)
(not necessarily in order). The algorithm is executed according to policy
. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true.For both overloads, if the iterator type is mutable, f
may modify the elements of the range through the dereferenced iterator. If f
returns a result, the result is ignored.
Unlike the rest of the algorithms, for_each is not allowed to make copies of the elements in the sequence even if they are trivially copyable.
Parameters
first, last | - | the range to apply the function to |
policy | - | the execution policy to use. See execution policy for details. |
f | - | function object, to be applied to the result of dereferencing every iterator in the range [first, last) The signature of the function should be equivalent to the following: void fun(const Type &a); The signature does not need to have const &. |
Type requirements | ||
-InputIt must meet the requirements of LegacyInputIterator.
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-ForwardIt must meet the requirements of LegacyForwardIterator.
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-UnaryFunction must meet the requirements of MoveConstructible. Does not have to be CopyConstructible
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-UnaryFunction2 must meet the requirements of CopyConstructible.
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Return value
f
(until C++11) std::move(f) (since C++11)Complexity
Exactly last
- first
applications of f
Exceptions
The overload with a template parameter named ExecutionPolicy
reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the three standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Possible implementation
template<class InputIt, class UnaryFunction> constexpr UnaryFunction for_each(InputIt first, InputIt last, UnaryFunction f) { for (; first != last; ++first) { f(*first); } return f; } |
Example
The following example uses a lambda function to increment all of the elements of a vector and then uses an overloaded operator()
in a functor to compute their sum. Note that to compute the sum, it is recommended to use the dedicated algorithm std::accumulate.
#include <vector> #include <algorithm> #include <iostream> struct Sum { Sum(): sum{0} { } void operator()(int n) { sum += n; } int sum; }; int main() { std::vector<int> nums{3, 4, 2, 8, 15, 267}; auto print = [](const int& n) { std::cout << " " << n; }; std::cout << "before:"; std::for_each(nums.begin(), nums.end(), print); std::cout << '\n'; std::for_each(nums.begin(), nums.end(), [](int &n){ n++; }); // calls Sum::operator() for each number Sum s = std::for_each(nums.begin(), nums.end(), Sum()); std::cout << "after: "; std::for_each(nums.begin(), nums.end(), print); std::cout << '\n'; std::cout << "sum: " << s.sum << '\n'; }
Output:
before: 3 4 2 8 15 267 after: 4 5 3 9 16 268 sum: 305
See also
applies a function to a range of elements (function template) | |
range-for loop | executes loop over range (since C++11) |
(C++17) |
applies a function object to the first n elements of a sequence (function template) |